PolyPolymorphism and Higher-Order Functions
Set Warnings "-notation-overridden,-parsing".
From LF Require Export Lists.
Polymorphism
Polymorphic Lists
Inductive boollist : Type :=
| bool_nil
| bool_cons (b : bool) (l : boollist).
... but this would quickly become tedious, partly because we
have to make up different constructor names for each datatype, but
mostly because we would also need to define new versions of all
our list manipulating functions (length, rev, etc.) and all
their properties (rev_length, app_assoc, etc.) for each
new datatype definition.
To avoid all this repetition, Coq supports polymorphic
inductive type definitions. For example, here is a polymorphic
list datatype.
Inductive list (X:Type) : Type :=
| nil
| cons (x : X) (l : list X).
This is exactly like the definition of natlist from the
previous chapter, except that the nat argument to the cons
constructor has been replaced by an arbitrary type X, a binding
for X has been added to the function header on the first line,
and the occurrences of natlist in the types of the constructors
have been replaced by list X.
What sort of thing is list itself? A good way to think about it
is that the definition of list is a function from Types to
Inductive definitions; or, to put it more concisely, list is a
function from Types to Types. For any particular type X,
the type list X is the Inductively defined set of lists whose
elements are of type X.
Check list : Type -> Type.
The parameter X in the definition of list automatically
becomes a parameter to the constructors nil and cons -- that
is, nil and cons are now polymorphic constructors; when we use
them, we must now provide a first argument that is the type of the
list they are building. For example, nil nat constructs the
empty list of type nat.
Check (nil nat) : list nat.
Similarly, cons nat adds an element of type nat to a list of
type list nat. Here is an example of forming a list containing
just the natural number 3.
Check (cons nat 3 (nil nat)) : list nat.
What might the type of nil be? We can read off the type
list X from the definition, but this omits the binding for X
which is the parameter to list. Type -> list X does not
explain the meaning of X. (X : Type) -> list X comes
closer. Coq's notation for this situation is forall X : Type,
list X.
Check nil : forall X : Type, list X.
Similarly, the type of cons from the definition looks like
X -> list X -> list X, but using this convention to explain the
meaning of X results in the type forall X, X -> list X -> list
X.
Check cons : forall X : Type, X -> list X -> list X.
(A side note on notations: In .v files, the "forall" quantifier
is spelled out in letters. In the generated HTML files and in the
way various IDEs show .v files, depending on the settings of their
display controls, forall is usually typeset as the standard
mathematical "upside down A," though you'll still see the
spelled-out "forall" in a few places. This is just a quirk of
typesetting -- there is no difference in meaning.)
Having to supply a type argument for every single use of a
list constructor would be rather burdensome; we will soon see ways
of reducing this annotation burden.
Check (cons nat 2 (cons nat 1 (nil nat)))
: list nat.
We can now go back and make polymorphic versions of all the
list-processing functions that we wrote before. Here is repeat,
for example:
Fixpoint repeat (X : Type) (x : X) (count : nat) : list X :=
match count with
| 0 => nil X
| S count' => cons X x (repeat X x count')
end.
As with nil and cons, we can use repeat by applying it
first to a type and then to an element of this type (and a number):
Example test_repeat1 :
repeat nat 4 2 = cons nat 4 (cons nat 4 (nil nat)).
Proof. reflexivity. Qed.
To use repeat to build other kinds of lists, we simply
instantiate it with an appropriate type parameter:
Example test_repeat2 :
repeat bool false 1 = cons bool false (nil bool).
Proof. reflexivity. Qed.
Module MumbleGrumble.
Inductive mumble : Type :=
| a
| b (x : mumble) (y : nat)
| c.
Inductive grumble (X:Type) : Type :=
| d (m : mumble)
| e (x : X).
Which of the following are well-typed elements of grumble X for
some type X? (Add YES or NO to each line.)
- d (b a 5)
- d mumble (b a 5)
- d bool (b a 5)
- e bool true
- e mumble (b c 0)
- e bool (b c 0)
- c
End MumbleGrumble.
Definition manual_grade_for_mumble_grumble : option (nat*string) := None.
Definition manual_grade_for_mumble_grumble : option (nat*string) := None.
☐
Type Annotation Inference
Fixpoint repeat' X x count : list X :=
match count with
| 0 => nil X
| S count' => cons X x (repeat' X x count')
end.
Indeed it will. Let's see what type Coq has assigned to repeat':
Check repeat'
: forall X : Type, X -> nat -> list X.
Check repeat
: forall X : Type, X -> nat -> list X.
It has exactly the same type as repeat. Coq was able to
use type inference to deduce what the types of X, x, and
count must be, based on how they are used. For example, since
X is used as an argument to cons, it must be a Type, since
cons expects a Type as its first argument; matching count
with 0 and S means it must be a nat; and so on.
This powerful facility means we don't always have to write
explicit type annotations everywhere, although explicit type
annotations can still be quite useful as documentation and sanity
checks, so we will continue to use them much of the time.
Type Argument Synthesis
Fixpoint repeat'' X x count : list X :=
match count with
| 0 => nil _
| S count' => cons _ x (repeat'' _ x count')
end.
In this instance, we don't save much by writing _ instead of
X. But in many cases the difference in both keystrokes and
readability is nontrivial. For example, suppose we want to write
down a list containing the numbers 1, 2, and 3. Instead of
this...
Definition list123 :=
cons nat 1 (cons nat 2 (cons nat 3 (nil nat))).
...we can use holes to write this:
Definition list123' :=
cons _ 1 (cons _ 2 (cons _ 3 (nil _))).
Implicit Arguments
Arguments nil {X}.
Arguments cons {X} _ _.
Arguments repeat {X} x count.
Now, we don't have to supply type arguments at all:
Definition list123'' := cons 1 (cons 2 (cons 3 nil)).
Alternatively, we can declare an argument to be implicit
when defining the function itself, by surrounding it in curly
braces instead of parens. For example:
Fixpoint repeat''' {X : Type} (x : X) (count : nat) : list X :=
match count with
| 0 => nil
| S count' => cons x (repeat''' x count')
end.
(Note that we didn't even have to provide a type argument to the
recursive call to repeat'''. Indeed, it would be invalid to
provide one, because Coq is not expecting it.)
We will use the latter style whenever possible, but we will
continue to use explicit Argument declarations for Inductive
constructors. The reason for this is that marking the parameter
of an inductive type as implicit causes it to become implicit for
the type itself, not just for its constructors. For instance,
consider the following alternative definition of the list
type:
Inductive list' {X:Type} : Type :=
| nil'
| cons' (x : X) (l : list').
Because X is declared as implicit for the entire inductive
definition including list' itself, we now have to write just
list' whether we are talking about lists of numbers or booleans
or anything else, rather than list' nat or list' bool or
whatever; this is a step too far.
Let's finish by re-implementing a few other standard list
functions on our new polymorphic lists...
Fixpoint app {X : Type} (l1 l2 : list X)
: (list X) :=
match l1 with
| nil => l2
| cons h t => cons h (app t l2)
end.
Fixpoint rev {X:Type} (l:list X) : list X :=
match l with
| nil => nil
| cons h t => app (rev t) (cons h nil)
end.
Fixpoint length {X : Type} (l : list X) : nat :=
match l with
| nil => 0
| cons _ l' => S (length l')
end.
Example test_rev1 :
rev (cons 1 (cons 2 nil)) = (cons 2 (cons 1 nil)).
Proof. reflexivity. Qed.
Example test_rev2:
rev (cons true nil) = cons true nil.
Proof. reflexivity. Qed.
Example test_length1: length (cons 1 (cons 2 (cons 3 nil))) = 3.
Proof. reflexivity. Qed.
Supplying Type Arguments Explicitly
Fail Definition mynil := nil.
(The Fail qualifier that appears before Definition can be
used with any command, and is used to ensure that that command
indeed fails when executed. If the command does fail, Coq prints
the corresponding error message, but continues processing the rest
of the file.)
Here, Coq gives us an error because it doesn't know what type
argument to supply to nil. We can help it by providing an
explicit type declaration (so that Coq has more information
available when it gets to the "application" of nil):
Definition mynil : list nat := nil.
Alternatively, we can force the implicit arguments to be explicit by
prefixing the function name with @.
Check @nil : forall X : Type, list X.
Definition mynil' := @nil nat.
Using argument synthesis and implicit arguments, we can
define convenient notation for lists, as before. Since we have
made the constructor type arguments implicit, Coq will know to
automatically infer these when we use the notations.
Notation "x :: y" := (cons x y)
(at level 60, right associativity).
Notation "[ ]" := nil.
Notation "[ x ; .. ; y ]" := (cons x .. (cons y []) ..).
Notation "x ++ y" := (app x y)
(at level 60, right associativity).
Now lists can be written just the way we'd hope:
Definition list123''' := [1; 2; 3].
Exercises
Exercise: 2 stars, standard, optional (poly_exercises)
Theorem app_nil_r : forall (X:Type), forall l:list X,
l ++ [] = l.
Proof.
intros X l. induction l.
- reflexivity.
- simpl.
rewrite IHl.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite IHl.
reflexivity.
Qed.
Theorem app_assoc : forall A (l m n:list A),
l ++ m ++ n = (l ++ m) ++ n.
Proof.
intros A l m n. induction l.
- reflexivity.
- simpl.
rewrite -> IHl.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite -> IHl.
reflexivity.
Qed.
Lemma app_length : forall (X:Type) (l1 l2 : list X),
length (l1 ++ l2) = length l1 + length l2.
Proof.
intros X l1 l2. induction l1.
- reflexivity.
- simpl.
rewrite -> IHl1.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite -> IHl1.
reflexivity.
Qed.
☐
Here are some slightly more interesting ones...
Exercise: 2 stars, standard, optional (more_poly_exercises)
Theorem rev_app_distr: forall X (l1 l2 : list X),
rev (l1 ++ l2) = rev l2 ++ rev l1.
Proof.
intros X l1 l2. induction l1.
- simpl.
rewrite app_nil_r.
reflexivity.
- simpl.
rewrite IHl1.
rewrite app_assoc.
reflexivity.
Qed.
- simpl.
rewrite app_nil_r.
reflexivity.
- simpl.
rewrite IHl1.
rewrite app_assoc.
reflexivity.
Qed.
Theorem rev_involutive : forall X : Type, forall l : list X,
rev (rev l) = l.
Proof.
intros X l. induction l.
- reflexivity.
- simpl.
rewrite rev_app_distr.
simpl.
rewrite IHl.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite rev_app_distr.
simpl.
rewrite IHl.
reflexivity.
Qed.
☐
Polymorphic Pairs
Inductive prod (X Y : Type) : Type :=
| pair (x : X) (y : Y).
Arguments pair {X} {Y} _ _.
As with lists, we make the type arguments implicit and define the
familiar concrete notation.
Notation "( x , y )" := (pair x y).
We can also use the Notation mechanism to define the standard
notation for product types:
Notation "X * Y" := (prod X Y) : type_scope.
(The annotation : type_scope tells Coq that this abbreviation
should only be used when parsing types, not when parsing
expressions. This avoids a clash with the multiplication
symbol.)
It is easy at first to get (x,y) and X*Y confused.
Remember that (x,y) is a value built from two other values,
while X*Y is a type built from two other types. If x has
type X and y has type Y, then (x,y) has type X*Y.
The first and second projection functions now look pretty
much as they would in any functional programming language.
Definition fst {X Y : Type} (p : X * Y) : X :=
match p with
| (x, y) => x
end.
Definition snd {X Y : Type} (p : X * Y) : Y :=
match p with
| (x, y) => y
end.
The following function takes two lists and combines them
into a list of pairs. In other functional languages, it is often
called zip; we call it combine for consistency with Coq's
standard library.
Fixpoint combine {X Y : Type} (lx : list X) (ly : list Y)
: list (X*Y) :=
match lx, ly with
| [], _ => []
| _, [] => []
| x :: tx, y :: ty => (x, y) :: (combine tx ty)
end.
Exercise: 1 star, standard, optional (combine_checks)
- What is the type of combine (i.e., what does Check @combine print?)
- What does
Compute (combine 1;2 false;false;true;true).print?
Check @combine: forall X Y : Type, list X -> list Y -> list (X * Y).
Check (combine [1;2] [false;false;true;true]) = [(1, false); (2, false)].
Check (combine [1;2] [false;false;true;true]) = [(1, false); (2, false)].
Exercise: 2 stars, standard, especially useful (split)
Fixpoint split {X Y : Type} (l : list (X*Y))
: (list X) * (list Y)
:= match l with
| [] => ([], [])
| (x, y)::t =>
let (xs, ys) := split t in
(x::xs, y::ys)
end.
| [] => ([], [])
| (x, y)::t =>
let (xs, ys) := split t in
(x::xs, y::ys)
end.
Example test_split:
split [(1,false);(2,false)] = ([1;2],[false;false]).
Proof.
reflexivity. Qed.
☐
Polymorphic Options
Module OptionPlayground.
Inductive option (X:Type) : Type :=
| Some (x : X)
| None.
Arguments Some {X} _.
Arguments None {X}.
End OptionPlayground.
We can now rewrite the nth_error function so that it works
with any type of lists.
Fixpoint nth_error {X : Type} (l : list X) (n : nat)
: option X :=
match l with
| nil => None
| a :: l' => match n with
| O => Some a
| S n' => nth_error l' n'
end
end.
Example test_nth_error1 : nth_error [4;5;6;7] 0 = Some 4.
Proof. reflexivity. Qed.
Example test_nth_error2 : nth_error [[1];[2]] 1 = Some [2].
Proof. reflexivity. Qed.
Example test_nth_error3 : nth_error [true] 2 = None.
Proof. reflexivity. Qed.
Exercise: 1 star, standard, optional (hd_error_poly)
Definition hd_error {X : Type} (l : list X) : option X
:= match l with
| [] => None
| h::t => Some h
end.
| [] => None
| h::t => Some h
end.
Check @hd_error : forall X : Type, list X -> option X.
Example test_hd_error1 : hd_error [1;2] = Some 1.
Proof. reflexivity. Qed.
Example test_hd_error2 : hd_error [[1];[2]] = Some [1].
Proof. reflexivity. Qed.
☐
Functions as Data
Higher-Order Functions
Definition doit3times {X:Type} (f:X->X) (n:X) : X :=
f (f (f n)).
The argument f here is itself a function (from X to
X); the body of doit3times applies f three times to some
value n.
Check @doit3times : forall X : Type, (X -> X) -> X -> X.
Example test_doit3times: doit3times minustwo 9 = 3.
Proof. reflexivity. Qed.
Example test_doit3times': doit3times negb true = false.
Proof. reflexivity. Qed.
Filter
Fixpoint filter {X:Type} (test: X->bool) (l:list X) : (list X) :=
match l with
| [] => []
| h :: t =>
if test h then h :: (filter test t)
else filter test t
end.
For example, if we apply filter to the predicate evenb
and a list of numbers l, it returns a list containing just the
even members of l.
Example test_filter1: filter evenb [1;2;3;4] = [2;4].
Proof. reflexivity. Qed.
Definition length_is_1 {X : Type} (l : list X) : bool :=
(length l) =? 1.
Example test_filter2:
filter length_is_1
[ [1; 2]; [3]; [4]; [5;6;7]; []; [8] ]
= [ [3]; [4]; [8] ].
Proof. reflexivity. Qed.
We can use filter to give a concise version of the
countoddmembers function from the Lists chapter.
Definition countoddmembers' (l:list nat) : nat :=
length (filter oddb l).
Example test_countoddmembers'1: countoddmembers' [1;0;3;1;4;5] = 4.
Proof. reflexivity. Qed.
Example test_countoddmembers'2: countoddmembers' [0;2;4] = 0.
Proof. reflexivity. Qed.
Example test_countoddmembers'3: countoddmembers' nil = 0.
Proof. reflexivity. Qed.
Anonymous Functions
Example test_anon_fun':
doit3times (fun n => n * n) 2 = 256.
Proof. reflexivity. Qed.
The expression (fun n => n * n) can be read as "the function
that, given a number n, yields n * n."
Here is the filter example, rewritten to use an anonymous
function.
Example test_filter2':
filter (fun l => (length l) =? 1)
[ [1; 2]; [3]; [4]; [5;6;7]; []; [8] ]
= [ [3]; [4]; [8] ].
Proof. reflexivity. Qed.
Exercise: 2 stars, standard (filter_even_gt7)
Definition filter_even_gt7 (l : list nat) : list nat
:= filter (fun x => (7 <? x) && (evenb x)) l.
Example test_filter_even_gt7_1 :
filter_even_gt7 [1;2;6;9;10;3;12;8] = [10;12;8].
Proof. reflexivity. Qed.
Example test_filter_even_gt7_2 :
filter_even_gt7 [5;2;6;19;129] = [].
Proof. reflexivity. Qed.
Exercise: 3 stars, standard (partition)
Definition partition {X : Type}
(test : X -> bool)
(l : list X)
: list X * list X
:= ( filter test l, filter (fun x => negb (test x)) l ).
Example test_partition1: partition oddb [1;2;3;4;5] = ([1;3;5], [2;4]).
Proof. reflexivity. Qed.
Example test_partition2: partition (fun x => false) [5;9;0] = ([], [5;9;0]).
Proof. reflexivity. Qed.
Fixpoint map {X Y: Type} (f:X->Y) (l:list X) : (list Y) :=
match l with
| [] => []
| h :: t => (f h) :: (map f t)
end.
It takes a function f and a list l = [n1, n2, n3, ...]
and returns the list [f n1, f n2, f n3,...] , where f has
been applied to each element of l in turn. For example:
Example test_map1: map (fun x => plus 3 x) [2;0;2] = [5;3;5].
Proof. reflexivity. Qed.
The element types of the input and output lists need not be
the same, since map takes two type arguments, X and Y; it
can thus be applied to a list of numbers and a function from
numbers to booleans to yield a list of booleans:
Example test_map2:
map oddb [2;1;2;5] = [false;true;false;true].
Proof. reflexivity. Qed.
It can even be applied to a list of numbers and
a function from numbers to lists of booleans to
yield a list of lists of booleans:
Example test_map3:
map (fun n => [evenb n;oddb n]) [2;1;2;5]
= [[true;false];[false;true];[true;false];[false;true]].
Proof. reflexivity. Qed.
Exercises
Exercise: 3 stars, standard (map_rev)
Lemma map_app : forall (X Y : Type) (f : X -> Y) (l1 l2 : list X),
map f (l1 ++ l2) = (map f l1) ++ (map f l2).
Proof.
intros X Y f l1 l2. induction l1.
- reflexivity.
- simpl.
rewrite IHl1.
reflexivity.
Qed.
map f (l1 ++ l2) = (map f l1) ++ (map f l2).
Proof.
intros X Y f l1 l2. induction l1.
- reflexivity.
- simpl.
rewrite IHl1.
reflexivity.
Qed.
Theorem map_rev : forall (X Y : Type) (f : X -> Y) (l : list X),
map f (rev l) = rev (map f l).
Proof.
intros X Y f l. induction l.
- reflexivity.
- simpl.
rewrite -> map_app.
rewrite -> IHl.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite -> map_app.
rewrite -> IHl.
reflexivity.
Qed.
Exercise: 2 stars, standard, especially useful (flat_map)
Fixpoint flat_map {X Y: Type} (f: X -> list Y) (l: list X)
: (list Y)
:= match l with
| [] => []
| h::t => f h ++ (flat_map f t)
end.
| [] => []
| h::t => f h ++ (flat_map f t)
end.
Example test_flat_map1:
flat_map (fun n => [n;n;n]) [1;5;4]
= [1; 1; 1; 5; 5; 5; 4; 4; 4].
Proof. reflexivity. Qed.
Definition option_map {X Y : Type} (f : X -> Y) (xo : option X)
: option Y :=
match xo with
| None => None
| Some x => Some (f x)
end.
Exercise: 2 stars, standard, optional (implicit_args)
Fold
Fixpoint fold {X Y: Type} (f: X->Y->Y) (l: list X) (b: Y)
: Y :=
match l with
| nil => b
| h :: t => f h (fold f t b)
end.
Intuitively, the behavior of the fold operation is to
insert a given binary operator f between every pair of elements
in a given list. For example, fold plus [1;2;3;4] intuitively
means 1+2+3+4. To make this precise, we also need a "starting
element" that serves as the initial second input to f. So, for
example,
fold plus 1;2;3;4 0
yields
1 + (2 + (3 + (4 + 0))).
Some more examples:
Check (fold andb) : list bool -> bool -> bool.
Example fold_example1 :
fold mult [1;2;3;4] 1 = 24.
Proof. reflexivity. Qed.
Example fold_example2 :
fold andb [true;true;false;true] true = false.
Proof. reflexivity. Qed.
Example fold_example3 :
fold app [[1];[];[2;3];[4]] [] = [1;2;3;4].
Proof. reflexivity. Qed.
Exercise: 1 star, advanced (fold_types_different)
A function to check whether each element of a nature number list
is not O, where f has type nat->bool->bool.
Definition manual_grade_for_fold_types_different : option (nat*string) := None.
☐
Functions That Construct Functions
Definition constfun {X: Type} (x: X) : nat->X :=
fun (k:nat) => x.
Definition ftrue := constfun true.
Example constfun_example1 : ftrue 0 = true.
Proof. reflexivity. Qed.
Example constfun_example2 : (constfun 5) 99 = 5.
Proof. reflexivity. Qed.
In fact, the multiple-argument functions we have already
seen are also examples of passing functions as data. To see why,
recall the type of plus.
Check plus : nat -> nat -> nat.
Each -> in this expression is actually a binary operator
on types. This operator is right-associative, so the type of
plus is really a shorthand for nat -> (nat -> nat) -- i.e., it
can be read as saying that "plus is a one-argument function that
takes a nat and returns a one-argument function that takes
another nat and returns a nat." In the examples above, we
have always applied plus to both of its arguments at once, but
if we like we can supply just the first. This is called partial
application.
Definition plus3 := plus 3.
Check plus3 : nat -> nat.
Example test_plus3 : plus3 4 = 7.
Proof. reflexivity. Qed.
Example test_plus3' : doit3times plus3 0 = 9.
Proof. reflexivity. Qed.
Example test_plus3'' : doit3times (plus 3) 0 = 9.
Proof. reflexivity. Qed.
Module Exercises.
Exercise: 2 stars, standard (fold_length)
Definition fold_length {X : Type} (l : list X) : nat :=
fold (fun _ n => S n) l 0.
Example test_fold_length1 : fold_length [4;7;0] = 3.
Proof. reflexivity. Qed.
Prove the correctness of fold_length. (Hint: It may help to
know that reflexivity simplifies expressions a bit more
aggressively than simpl does -- i.e., you may find yourself in a
situation where simpl does nothing but reflexivity solves the
goal.)
Theorem fold_length_correct : forall X (l : list X),
fold_length l = length l.
Proof.
intros X l. induction l.
- reflexivity.
- simpl.
rewrite <- IHl.
reflexivity.
Qed.
- reflexivity.
- simpl.
rewrite <- IHl.
reflexivity.
Qed.
☐
We can also define map in terms of fold. Finish fold_map
below.
Exercise: 3 stars, standard (fold_map)
Definition fold_map {X Y: Type} (f: X -> Y) (l: list X) : list Y
:= fold (fun x ys => (f x)::ys) l [].
Theorem fold_map_correct : forall X Y (f: X -> Y) (l: list X),
fold_map f l = map f l.
Proof.
intros X Y f l. induction l.
- reflexivity.
- simpl.
rewrite <- IHl.
reflexivity.
Qed.
fold_map f l = map f l.
Proof.
intros X Y f l. induction l.
- reflexivity.
- simpl.
rewrite <- IHl.
reflexivity.
Qed.
Definition manual_grade_for_fold_map : option (nat*string) := None.
☐
In Coq, a function f : A -> B -> C really has the type A
-> (B -> C). That is, if you give f a value of type A, it
will give you function f' : B -> C. If you then give f' a
value of type B, it will return a value of type C. This
allows for partial application, as in plus3. Processing a list
of arguments with functions that return functions is called
currying, in honor of the logician Haskell Curry.
Conversely, we can reinterpret the type A -> B -> C as (A *
B) -> C. This is called uncurrying. With an uncurried binary
function, both arguments must be given at once as a pair; there is
no partial application.
We can define currying as follows:
Exercise: 2 stars, advanced (currying)
Definition prod_curry {X Y Z : Type}
(f : X * Y -> Z) (x : X) (y : Y) : Z := f (x, y).
As an exercise, define its inverse, prod_uncurry. Then prove
the theorems below to show that the two are inverses.
Definition prod_uncurry {X Y Z : Type}
(f : X -> Y -> Z) (p : X * Y) : Z
:= match p with | (x, y) => f x y end.
Example test_map1': map (plus 3) [2;0;2] = [5;3;5].
Proof. reflexivity. Qed.
Thought exercise: before running the following commands, can you
calculate the types of prod_curry and prod_uncurry?
Check @prod_curry.
Check @prod_uncurry.
Theorem uncurry_curry : forall (X Y Z : Type)
(f : X -> Y -> Z)
x y,
prod_curry (prod_uncurry f) x y = f x y.
Proof.
intros X Y Z f x y.
reflexivity.
Qed.
reflexivity.
Qed.
Theorem curry_uncurry : forall (X Y Z : Type)
(f : (X * Y) -> Z) (p : X * Y),
prod_uncurry (prod_curry f) p = f p.
Proof.
intros X Y Z f [x y].
reflexivity.
Qed.
reflexivity.
Qed.
☐
Recall the definition of the nth_error function:
Fixpoint nth_error {X : Type} (l : list X) (n : nat) : option X :=
match l with
| ☐ => None
| a :: l' => if n =? O then Some a else nth_error l' (pred n)
end.
Write an informal proof of the following theorem:
forall X l n, length l = n -> @nth_error X l n = None
Exercise: 2 stars, advanced (nth_error_informal)
Definition manual_grade_for_informal_proof : option (nat*string) := None.
☐
The following exercises explore an alternative way of defining
natural numbers, using the so-called Church numerals, named
after mathematician Alonzo Church. We can represent a natural
number n as a function that takes a function f as a parameter
and returns f iterated n times.
Module Church.
Definition cnat := forall X : Type, (X -> X) -> X -> X.
Let's see how to write some numbers with this notation. Iterating
a function once should be the same as just applying it. Thus:
Definition one : cnat :=
fun (X : Type) (f : X -> X) (x : X) => f x.
Similarly, two should apply f twice to its argument:
Definition two : cnat :=
fun (X : Type) (f : X -> X) (x : X) => f (f x).
Defining zero is somewhat trickier: how can we "apply a function
zero times"? The answer is actually simple: just return the
argument untouched.
Definition zero : cnat :=
fun (X : Type) (f : X -> X) (x : X) => x.
More generally, a number n can be written as fun X f x => f (f
... (f x) ...), with n occurrences of f. Notice in
particular how the doit3times function we've defined previously
is actually just the Church representation of 3.
Definition three : cnat := @doit3times.
Complete the definitions of the following functions. Make sure
that the corresponding unit tests pass by proving them with
reflexivity.
Successor of a natural number: given a Church numeral n,
the successor succ n is a function that iterates its
argument once more than n.
Exercise: 1 star, advanced (church_succ)
Definition succ (n : cnat) : cnat
:= fun (X : Type) (f : X -> X) (x : X) => f (n X f x).
Example succ_1 : succ zero = one.
Proof.
reflexivity. Qed.
Example succ_2 : succ one = two.
Proof.
reflexivity. Qed.
Example succ_3 : succ two = three.
Proof.
reflexivity. Qed.
Definition plus (n m : cnat) : cnat
:= fun (X : Type) (f : X -> X) (x : X) => m X f (n X f x).
Example plus_1 : plus zero one = one.
Proof.
reflexivity. Qed.
Example plus_2 : plus two three = plus three two.
Proof.
reflexivity. Qed.
Example plus_3 :
plus (plus two two) three = plus one (plus three three).
Proof.
reflexivity. Qed.
Definition mult (n m : cnat) : cnat
:= fun (X : Type) (f : X -> X) => m X (n X f).
Example mult_1 : mult one one = one.
Proof.
reflexivity. Qed.
Example mult_2 : mult zero (plus three three) = zero.
Proof.
reflexivity. Qed.
Example mult_3 : mult two three = plus three three.
Proof.
reflexivity. Qed.
Exercise: 2 stars, advanced (church_exp)
Definition exp (n m : cnat) : cnat
:= fun (X : Type) => m (X -> X) (n X).
Example exp_1 : exp two two = plus two two.
Proof.
reflexivity. Qed.
Example exp_2 : exp three zero = one.
Proof.
reflexivity. Qed.
Example exp_3 : exp three two = plus (mult two (mult two two)) one.
Proof.
reflexivity. Qed.
End Church.
End Exercises.
